A reaction is of second order with respect to its reactant. How will its reaction rate be affected if the concentration of the reactant is (i) doubled (ii) reduced to half ?

Explanation

To solve the problem step by step, we will analyze how the rate of a second-order reaction is affected by changes in the concentration of the reactant.

### Step 1: Understand the Rate Law for a Second-Order Reaction
For a second-order reaction with respect to a single reactant, the rate law can be expressed as:
\[ R = k[A]^2 \]
where:
- \( R \) is the rate of the reaction,
- \( k \) is the rate constant,
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