What is the formula of a compound in which the element Y forms ccp lattice and atoms of X occupy `2//3^(rd)` of tetrahedral voids ?

Explanation

To find the formula of the compound in which element Y forms a cubic close-packed (ccp) lattice and atoms of X occupy \( \frac{2}{3} \) of the tetrahedral voids, we can follow these steps:

### Step 1: Determine the number of atoms of Y in the ccp lattice.
In a cubic close-packed (ccp) lattice, there are 4 effective atoms of Y per unit cell. Therefore, we can denote the number of atoms of Y as \( n = 4 \).

### Step 2: Calculate the number of tetrahedral voids.
In a ccp lattice, the number of tetrahedral voids is twice the number of atoms present in the unit cell. Hence, the number of tetrahedral voids is:
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