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Calculate the time required to deposit 1.27 g of copper at cathode when a current of 2A was passed through the solution of `CuSO_(4)`.
`("Molar mass of "Cu=63.5g mol^(-1), 1F =96500 C mol^(-1)).`

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To calculate the time required to deposit 1.27 g of copper at the cathode when a current of 2 A is passed through a solution of CuSO₄, we can use Faraday's first law of electrolysis. Here’s a step-by-step solution: ### Step 1: Determine the Equivalent Weight of Copper The equivalent weight (E) can be calculated using the formula: \[ E = \frac{\text{Molar mass}}{n} \] where: ...
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