What happens when
(i) chlorobenzene is treated with `Cl_(2)//FeCl_(3)`
(ii) ethyl chloride is treated with `AgNO_(2),`
(iii) 2-bromopentane is treated with alcoholic KOH ?
Write the chemical equations in support of your answer.

Explanation

(i) Chlorobenzene is treated with `Cl_(2)//FeCl_(3).`

In the presence of an iron catalyst, chlorine reacts repidly with benzene to give chlorobenzene and `HCl FeCl_(3),` catalyst substitutes a halogen for an H.
(ii) Ethyl chloride is treated with `AgNO_(2)` Victor-Mayer Method :
`CH_(3)CH_(2)Cl+AgNO_(2)rarrCH_(3)CH_(2)NO_(2)+AgCl`
(iii) 2-bromopentane is treated with alcoholic KOH
`CH_(3)-overset(Br)overset(|)CH-CH_(2)-CH_(2)-CH_(3)overset(KOH(al.Delta))rarrCH_(3)-CH=CH-CH_(2)-CH_(3)+HBr`