Home
Class 12
CHEMISTRY
Conductivity of 2.5xx10^(-4) M methanoic...

Conductivity of `2.5xx10^(-4)` M methanoic acid is `5.25xx10^(-5)S com^(-1)`. Calculate its molar conductivity and degree of dissociation.
`"Given ":lamda^(0)(H^(+))=349.5 S cm^(2) mol^(-1) and lamda^(0)(HCOO^(-))=50.5 S cm^(2) mol^(-1).`

Text Solution

AI Generated Solution

To solve the problem, we will follow these steps: ### Step 1: Calculate Molar Conductivity (Λm) Molar conductivity (Λm) is calculated using the formula: \[ \Lambda_m = \frac{1000 \times \kappa}{C} ...
Promotional Banner

Similar Questions

Explore conceptually related problems

The conductivity of 0.001 "mol" L^(-1) solution of CH_(3)COOH " is " 3.905 xx 10^(-5) "S" cm^(-1) . Calculate its molar conductivity and degree of dissociation (alpha) . "Given" lambda^(@) (H^(+)) = 349.6 "S" cm^(2) "mol"^(-1) " and " lambda^(0) (CH_(3)COO^(-)) = 40.9 "S" cm^(2) per mol)

The molar conductivity of 0.25 mol L^(-1) methanoic acid is 46.1 S cm^(2) mol^(-1) . Calculate the degree of dissociation constant. Given : lambda_((H^(o+)))^(@)=349.6S cm^(2)mol^(-1) and lambda_(HCOO^(-))^(@)=54.6Scm^(2)mol^(-1)

The molar conductivity of 0.025 mol L^(-1) methanoic acid is 46.1 S cm^(2) mol^(-1) . Its degree of dissociation (alpha) and dissociation constant. Given lambda^(@)(H^(+))=349.6 S cm^(-1) and lambda^(@)(HCOO^(-)) = 54.6 S cm^(2) mol^(-1) .

Conductivity of 0.12 M CuSO_(4) solution at 298 K is 1.8 xx 10^(-2) S cm^(-1) Calculate its equivalent conductivity

The conductivity of a 0.01 M solution of acetic acid at 298 k is 1.65xx10^(-4) S cm ^(-1) . Calculate molar conductivity (wedge_(m)) of the solution.

The conductivity of a 0.01 M solution of acetic acid at 298 k is 1.65xx10^(-4) S cm ^(-1) . Calculate molar conductivity (wedge_(m)) of the solution.

Conductivity of 0.003 M sulphuric acid is 6.896xx10^(-5)"S "cm^(-1) . Calculate its molar conductivity and if wedge^(@)m for sulphuric acid is 490.5 Scm^(2)mol^(-1) , what is its dissociation constant?

The conductivity of 0.00241 M acetic acid is 7.896xx10^(-5)Scm^(-1) . Calculate its molar conductivity. If wedge_(m)^(@) for acetic acid is 390.5Scm^(2)mol^(-1) , what is its dissociation constant ?

Calculate the degree of dissociation (alpha) of acetic acid if its molar conductivity is 39.05 Scm^(2)mol^(-1) . Given lamda^(@)(H^(+))=349.6S" "cm^(2)mol^(-1) and lamda^(@)(CH_(3)CO O^(-))=40.9" S "cm^(2)mol^(-1) .

The conductivity of 0*2M " KCl solution is " 3 Xx 10^(-2) ohm^(-1) cm^(-1) . Calculate its molar conductance.