An element with density `11.2 g cm^(-3)` forms a f. c. c. lattice with edge length of `4xx10^(-8)` cm. Calculate the atomic mass of the element. (Given : `N_(A)= 6.022xx10^(23) mol^(-1)`

Explanation

To calculate the atomic mass of the element with a given density and edge length of a face-centered cubic (FCC) lattice, we can use the formula for density:

\[ \text{Density} = \frac{Z \times M}{V \times N_A} \]

Where:
- \( Z \) = number of atoms per unit cell (for FCC, \( Z = 4 \))
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