(a) Define the following terms :
(i) Limiting molar conductivity,
(ii) Fuel cell
(b) Resistance of a conductivity cell filled with `0.1 molL^(-1)KCl` solution is 100 Ohm. If the resistance of the same cell when filled with `0.2 mol L^(-1)KCl` solution is 520 Ohm , calculate the conductivity and molar conductivity of `0.2 mol L^(-1) KCl` solution. The conductivity of `0.1 mol L^(-1) KCl` solution is ` 1.29xx10^(-1) Scm^(-1)` .

Explanation

### Step-by-Step Solution

#### Part (a): Definitions

**(i) Limiting Molar Conductivity:**
Limiting molar conductivity (Λm) is defined as the molar conductivity of an electrolyte solution as the concentration approaches zero (infinite dilution). It represents the maximum conductivity that can be achieved by the electrolyte when it is fully dissociated into its ions. Mathematically, it can be expressed as:
\[ \Lambda_m = \lim_{C \to 0} \Lambda_m(C) \]
where \( \Lambda_m(C) \) is the molar conductivity at concentration \( C \).
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