In the circuit shown, `R_1=2 Omega,R_2=R_3=10Omega and E=6V`. Work out the equivalent resistance of the circuit and the current in each resistor.

In the circuit shown, R_1=2 Omega,R_2=R_3=10Omega, R_4=20Omega and E=6V . Work out the equivalent resistance of the circuit and the current in each resistor.

In the circuit shown, R_1=4Omega,R_2=R_3=15Omega,R_4=30OmegaandE=10V . Caculate the equivalent resistance of te circuit and the current in each resistor.

In the circuit shown, the current in the 1Omega resistor is :

In the given circuit, R_(1) = 10Omega R_(2) = 6Omega and E = 10V, then correct statement is

In the given circuit, E=8 V,R_1=1Omega, R_2=R_3=R_4=5Omega .The current through the resistance R_4 is (in A):

If the resistance of each branch of the circuit shown below is 1 Omega , then the equivalent resistance of the circuit between the points A and B is

In the curcuit shown in figure R_1=R_2=R_3=10Omega . Find the currents through R_1 and R_2

Find the equivalent resistance of the circuit shown in figure between the points a and b.Each resistor has a resistances r .

In the circuit shown, each resistor is of resistance R. the equivalent resistance between the terminals A and B is

The current in the resistor R_3 in the circuit as shown in the figure is