In the circuit shown, `R_1=2 Omega,R_2=R_3=10Omega, R_4=20Omega and E=6V`. Work out the equivalent resistance of the circuit and the current in each resistor.

In the circuit shown, R_1=2 Omega,R_2=R_3=10Omega and E=6V . Work out the equivalent resistance of the circuit and the current in each resistor.

In the circuit shown, R_1=4Omega,R_2=R_3=15Omega,R_4=30OmegaandE=10V . Caculate the equivalent resistance of te circuit and the current in each resistor.

In the given circuit, E=8 V,R_1=1Omega, R_2=R_3=R_4=5Omega .The current through the resistance R_4 is (in A):

In the given circuit, R_(1) = 10Omega R_(2) = 6Omega and E = 10V, then correct statement is

(a) Resistors given as R_(1), R_(2) and R_(3) are connected in series to a battery V. Draw the circuit diagram showing the arrangement. Derive an expression for the equivalent resistance of the combination. (b) If R_(1)=10 Omega, R_(2)=20 Omega and R_(3)=30 Omega , calculate the effective resistance when they are connected in series to a battery of 6 V. Also find the current flowing in the circuit.

In the circuit shown below, E_(1)=17V,E_(2)=21V,R_(1)=2Omega,R_(2)=3Omega and R_(3)=5Omega . Using Kirchhoff.s laws, find the currents flowing through the resistors R_(1),R_(2) and R_(3) . (Internal resistance of each of the batteries is negligible.)

In the curcuit shown in figure R_1=R_2=R_3=10Omega . Find the currents through R_1 and R_2

In the circuit shown in figure E_1=10 V, E_2=4V, r_1=r_2=1Omega and R=2Omega . Find the potential difference across battery 1 and battery 2.

In the circuit shown in figure E_1=10 V, E_2=4V, r_1=r_2=1Omega and R=2Omega . Find the potential difference across battery 1 and battery 2.

In the circuit shown in fig. R_(1) = 10 Omega, R_(2) = 5 Omega, C_(1) = 1 muF, C_(2) = 2muF, and E =6V. Calculate the charge on each capactor in the stedy state.