Home
Class 12
PHYSICS
The figure, drawn here, shows the geomet...

The figure, drawn here, shows the geometry of path differences for diffraction by a single slit of width a.

Given appropriate reasoning to explain why the intensity of light is
(i) maximum of the central point C on the screen.
(ii) (nearly) zero for point P on the screen when `theta=lamda//a`.
Hence, write an expression for the total linear width of the central maxima on a screen kept at a distance D from the plane of the slit.

Promotional Banner

Similar Questions

Explore conceptually related problems

In a single slit diffraction of light of wavelength lambda by a slit of width e, the size of the central maximum on a screen at a distance b is

The angular width of the central maximum of the diffraction patternn in a single slit (of width a) experiment, with lamda as the wavelenth of light, is

In the experiment of diffraction at a single slit, if the slit width is decreased, the width of the central maximum

Angular width of central maximum in diffraction at a single slit is……………. .

In diffraction froma a single -slit, the angular width of the centre maxima does not depends on

In single sit diffraction experiment, the width of the central maximum inversely proportional to

In a Young’s double slit experiment, the ratio of the slit’s width is 4 : 1. The ratio of the intensity of maxima to minima, close to the central fringe on the screen, will be:

Light of wavelength 5000 A^(0) is incident on a slit. The first minimum of the diffraction pattern is observed to lie at a distance of 5 mm from the central maximum on a screen placed at a distance of 3 m from the slit. Then the width of the slit is

A single slit of width d is placed in the path of beam of wavelength lamda . The angular width of the principal maximum obtained is-

Fraunhofer diffraction from a single slit of width 1.24 xx 10^(-6)m is observed with the light of wavelength 6200 Å. Calculate the angular width of the central maximum.