A resistance of R draws current from a potentiometer. The potentiometer wire, AB , has a total resistance of `R_(0)`, A voltage V is supplied to the potentiometer. Derive an expression for the voltage across R when the sliding contact is in the middle of potentialmeter wire.

AB is wire of potentiometer with the increase in the value of resistance R, the shift in the balance point J will be

A constant voltage V_(0) is applied to a potentiometer of resistance R connected to an ammeter. A constant resistor r is connected to the sliding contact of the potentiometer and the fixed end of the potentiometer. If the reading of ammeter vary as the sliding contact is moved from one end of the potentiometer to the other. The resistance of ammeter is assumed to be negligible. Find the minimum reading of the Ammeter.

If the resistance of potentiometer wire is 15r then calculate the balance length l

In given figure, the potentiometer wire AB has a resistance of 5 Omega and length 10 m . The balancing length AM for the emf of 0.4 V is

There is a potentiometer wire of length 1200 cm and 60 mA current is flowing in it. A battery of emf 5V and internal resistance of 20 ohm is balanced on potentiometer wire with balancing length 1000 cm. The resistance of potentiometer wire is

The potentiometer wire is of length 1200 cam and it carries a current of 60 mA. For a cell of emf 5V and internal resistance of 20Omega , the null point of it is found to be at 1000 cm.The resistance of potentiometer wire is

To the potentiometer wire of L and 10Omega resistance, a battery of emf 2.5 volts and a resistance R are connected in series. If a potential difference of 1 volt is balanced across L/2 length, the value of R is Omega will be

AN ideal battery of 4 V and resistance R are connected in series in the primary circuit of a potentiometer of length 1 m and and resistance 5Ω the value of R, to give a difference of 56mV across 10 cm of potentiometer wire , is :

The length of the potentiometer wire is 600 cm and a current of 40 mA is flowing in it. When a cell of emf 2 V and internal resistance 10Omega is balanced on this potentiometer the balance length is found to be 500 cm. The resistance of potentiometer wire will be

Assertion : Potentiometer is used only to compare potential differences. Reason: The potentiometer draws current from the voltage source being measured .