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Iron has a body centered cubic unit cell...

Iron has a body centered cubic unit cell with a cell edge of `286.65` pm . The density of iron is `7.87 g cm^(-3)` . Use this information to calculate Avogadro's number (At. Mass of Fe = 56g `mol^(-1)`).

Text Solution

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`d= 7.87 g cm^(-3)`,
For bec, `Z = 2, M = 56 g mol^(1)`
`a = 286.65 "pm" = 286.65xx10^(-10) cm , N_(A) =?`
`d = (Z xx M)/(N_(A) x a^(3))`
`N_(A) = (Z xx M)/(d xx a^(3))`
`N_(A) = (2xx55.845)/(7.874xx(286.65 xx 10^(-10)cm)^(3))`
`N_(A) = 6.03 xx 10^(23)` atom/mol.
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