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What mass of NaCI ("molar mass" =58.5g m...

What mass of `NaCI ("molar mass" =58.5g mol^(-1))` be dissolved in `65g` of water to tower the freezing point by `7.5^(@)C`? The freezing point depression constant, `K_(f)`, for water is `1.86 K kg mol^(-1)`. Assume van't Hoff factor for `NaCI` is `1.87`.

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To solve the problem step by step, we will use the formula for freezing point depression: \[ \Delta T_f = K_f \cdot m \cdot i \] Where: - \(\Delta T_f\) = depression in freezing point (in °C) ...
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