Vernier Calliperes

The Vernier constant of a Vernier Callipers is

The man scale of a Vernier Callipers reads in millimeter and its vernier is divided into 10 divisions which coincides with 9 divisions of the main scale. The length of the object for situation is found to be (x/10) mm. Find the value of x.

If in a Vernier callipers 10 VSD coincides with 8 MSD, then the least count of Vernier calliper is [given 1 MSD = 1mm]

Smallest division on the main scale of given Vernier calipers is 0.5 mm. Vernier scale has 25 divisions and these coincide with 24 main scale divisions. The least count of Vernier callipers is

The diameter of a cylinder is measured using a Vernier callipers with no zero error. It is found that the zero of the Vernier scale lies between 5.10cm and 5.15cm of the main scale. The Vernier scale has 50 divisions equivalent to 2.45 cm . The 24^(th) division of the Vernier scale exactly coincides with one of the main scale divisions. the diameter of the cylinder is

Consider a Vernier callipers in which each 1cm on the main scale is divided into 8 equal divisions and a screw gauge with 100 divisions in its circular scale. In the Vernier callipers, 5 divisions of the Vernier scale coincide with 4 divisions on the scale and in the screw gauge, one complete rotation of the circular scale moves it by two divisions on the linear scale. Then :

The least count of a vernier callipers is :

State three uses of a vernier callipers.

A vernier callipers having 1 main scale division = 0.1 cm to have a least count of 0.02 cm .If n be the number of divisions on vernier scale and m be the length of vernier scale, then.

In a vernier callipers n divisions of its main scale match with (n+5) divisions on its vernier scale. Each division of the main scale is of x unit. Using the vernier principle, find the least count.