Equations of Motion

A force F = - 10x + 2 acts on a particle of mass 0.1 kg where x is in m and F in newton. If is released from rest at x = 0 , find: a. Amplitude: b. Time period: c. Equation of motion.

Equation of motion of a body is (dv)/(dt) = -4v + 8, where v is the velocity in ms^-1 and t is the time in second. Initial velocity of the particle was zero. Then,

As a result of adding two mutually perpendicular oscillations of equal frequency the motion of an object occurs alongan ellipse, in one case the motion is clockwise, while in the other it is counter clockwise . Write the equations of motion along each coordinate axis, assuming that the initial phase along the x-axis is zero.

Equation of motion for a particle performing damped harmonic oscillation is given as x=e^(-1t) cos(10pit+phi) . The time when amplitude will half of the initial is :

Equation of motion in the same direction is given by y_(1) =A sin (omega t - kx), y_(2) = A sin ( omega t - kx- theta ) . The amplitude of the medium particle will be

Equation of motion for a particle performing damped harmonic oscillation is given as x=e^(-0.1t) cos(10pit+phi) . The time when amplitude will half of the initial is :

The equation of motion of a simple harmonic motion is not

The equation of motion of a simple harmonic motion is

Write the first equation of motion ?

The equation of motion may be given by