The threshold wavelength for two photosensitive surfaces A and B are `lambda`1 and `lambda`2 respectively. What is the ratio of the work functions of the two surfaces?

The threshold wavelength for emission of photoelectrons from a metal surface is 6 xx 10^(-7) m. What is the work function of the material of the metal surface ?

The maximum kinetic energy of photoelectron is doubled when the wavelength of light incident on the photosensitive changes from lambda_1 to lambda_2 . Deduce expression for the threshold wavelength and work function for metals in terms of lambda_1 and lambda_2

Find the threshold wavelengths for photoelectric effect from a copper surface, a sodium surface and a cesium surface. The work functions of these metals are 4.5 eV, 2.3 eV and 1.9 eV respectively.

The wavelengths of photons emitted by electron transition between two similar leveis in H and He^(+) are lambda_(1) and lambda_(2) respectively. Then :-

The wavelengths of photons emitted by electron transition between two similar leveis in H and He^(+) are lambda_(1) and lambda_(2) respectively. Then :-

Two metal spheres have radii rand 2r and they emit thermal radiation with maximum intensities at wavelengths lambda and 2lambda . respectively. The respective ratio of the radiant energy emitted by them per second will be

The wavelength of the short radio waves, microwaves, ultraviolet waves are lambda_(1),lambda_(2) and lambda_(3) , respectively, Arrange them in decreasing order.

Light of wavelength 4000A∘ is incident on a metal surface. The maximum kinetic energy of emitted photoelectron is 2 eV. What is the work function of the metal surface?

Two separate monochromatic light beams A and B of the same intensity (energy per unit area per unit time) are falling normally on a unit area of a metallic surface. Their wavelength are lambda_(A) and lambda_(B) respectively. Assuming that all the the incident light is used in ejecting the photoelectrons, the ratio of the number of photoelectrons from beam A to that from B is

If lambda_(0) is the threshold wavelength for photoelectric emission. lambda wavelength of light falling on the surface on the surface of metal, and m mass of electron. Then de Broglie wavelength of emitted electron is :-