Home
Class 12
Physics
Answer the following: (A) Two electric...

Answer the following:
(A) Two electric field lines cannot cross each other. Also, they cannot form closed loops. Give reasons.
(B) A particle of charge 2 `muC` and mass `1.6` g is moving with a velocity `4 hati ms^(-1)`.At `t=0` the particle enters in a region having an electric field `vecE`( in `NC^(-1)`) = `80hati + 60hatj`. Find the velocity of the particle at `t =5 s`

Promotional Banner

Similar Questions

Explore conceptually related problems

A particle of mass 1 g moving with a velocity vecv_1=3hati-2hatj m s^(-1) experiences a perfectly in elastic collision with another particle of mass 2 g and velocity vecv_2=4hatj-6 hatk m s^(-1) . The velocity of the particle is

A particle of charge 1 mu C & mass 1 g moving with a velocity of 4 m//s is subjected to a uniform electric field of magnitude 300 V m for 10 sec . Then it's final speed cannot be :

A charged particle ( mass m and charge q) moves along X axis with velocity V_0 . When it passes through the origin it enters a region having uniform electric field vecE=-E hatj which extends upto x=d . Equation of path of electron in the region . x gt d is :

A charged particle of charge 1 mC and mass 2g is moving with a speed of 5m/s in a uniform magnetic field of 0.5 tesla. Find the maximum acceleration of the charged particle

A charged particle of charge 1 mC and mass 2g is moving with a speed of 5m/s in a uniform magnetic field of 0.5 tesla. Find the maximum acceleration of the charged particle

A charged particle of specific charge (i.e.,Charge per unit mass 0 0.2 C/kg has velocity 2hati-3hatjms^(-1) at some instant in a uniform magnetic field 5hati+2hatj (tesla).Find the acceleration of the particle at this instant

A particle moves with a velocity v=(5hati-3hatj + 6hatk) ms^(-1) under the influence of a constant force F =(10hati + 10hatj + 20hath) N , the instantaneous power applied to the particle is.

A particle moves with a velocity v=(5hati-3hatj + 6hatk) ms^(-1) under the influence of a constant force F =(10hati + 10hatj + 20hath) N , the instantaneous power applied to the particle is.

A particle moves with a velocity of (4hati-2hatj+2hatk)ms^(-1) under the influence of a constant force vecF=(10hati+3hatj-2hatk)N . The instantaneous power applied to the particle is

V_(x) is the velocity of a particle of a particle moving along the x- axis as shown. If x=2.0m at t=1.0s , what is the position of the particle at t=6.0s ?