Given `triangle ABC ~ triangle PQR` if `(AB)/(PQ)=1/3` then find `(ar triangle ABC)/(ar triangle PQR)`

In figures triangle ABC and triangleDEF ar similar , the areas of triangle ABC is 9 sq. m and that of triangleDEF is 16 sq. cm. if EF= 4.2 cm, find BC.

In the given triangle ABC, find AE.

In a triangle ABC, if sin A sin B= (ab)/(c^(2)) , then the triangle is :

If in a triangle ABC , cosA=(sinB)/(2sinC) then the triangle ABC , is

In a triangle ABC,vertex angles A,B,C and side BC are given .The area of triangle ABC is

In triangle PQR. angleQ is a right angle, QR=24, and PR=26. Triangle YXZ is similar to triangle PQR, where vertices X, Y, and Z correspond to vertices P, Q, and R, respectively, and each side of triangle XYZ is (1)/(2) the length of the corresponding side of triangle PQR. What is the value of sin Z?

Let ABC be a triangle of area 24sq.units and PQR be the triangle formed by the mid-points of the sides triangle ABC. Then what is the area of triangle PQR.

In a triangle ABC if angle ABC=60^(@) , then ((AB-BC+CA)/(r ))^(2)=

Triangle ABC is similar to triangle PQR. If AD and PM are corresponding medians of the two triangles, prove that : (AB)/(PQ) = (AD)/(PM)

PQR is a triangle right angled at P. If PQ=10cm and PR=24cm, find QR