The angle of elevation of an airplane from a point on the ground is `60^(@)`. After a flight of 30 seconds, the angle of elevation becomes `30^(@)`. If the airplane is flying at a constant height of `3000sqrt(3)`m, find the speed of the airplane.

Explanation

To solve the problem step by step, we will analyze the situation using trigonometric principles.

### Step 1: Understand the Problem
We have an airplane flying at a constant height of \( 3000\sqrt{3} \) meters. The angle of elevation from a point on the ground to the airplane changes from \( 60^\circ \) to \( 30^\circ \) after 30 seconds.

### Step 2: Draw a Diagram
Let's label the points:
- Let \( A \) be the point on the ground from where the angles are measured.
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