The sum of the zeroes of the polynomial `2x^(2) - 8x+ 6` is

Options

A. `-3 `
B. `3`
C. `-4`
D. `4`

Explanation

To find the sum of the zeroes of the polynomial \(2x^2 - 8x + 6\), we can use the formula for the sum of the zeroes of a quadratic polynomial \(ax^2 + bx + c\), which is given by:

\[ \text{Sum of zeroes} = -\frac{b}{a} \]

### Step-by-step Solution:

1. **Identify the coefficients**:
In the polynomial \(2x^2 - 8x + 6\), we identify the coefficients:
- \(a = 2\) (coefficient of \(x^2\))
- \(b = -8\) (coefficient of \(x\))
- \(c = 6\) (constant term)

2. **Apply the formula**:
We will substitute the values of \(a\) and \(b\) into the formula:
\[ \text{Sum of zeroes} = -\frac{b}{a} = -\frac{-8}{2} \]

3. **Calculate the sum**:
Simplifying the expression:
\[ \text{Sum of zeroes} = \frac{8}{2} = 4 \]

4. **Final answer**:
Therefore, the sum of the zeroes of the polynomial \(2x^2 - 8x + 6\) is \(4\).