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Prove that: " "( tan A...

Prove that: `" "( tan A + sinA)/(tanA - sinA) = (sec A +1)/(secA -1)`

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To prove that \[ \frac{\tan A + \sin A}{\tan A - \sin A} = \frac{\sec A + 1}{\sec A - 1} \] we will start with the left-hand side (LHS) and manipulate it to show that it equals the right-hand side (RHS). ...
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