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(i) State Maxwell's right-hand thumb rul...

(i) State Maxwell's right-hand thumb rule.
(ii) PQ is a current carrying conductor in the plane of the paper as shown in the figure. Mention the direction of magnetic fields produced by it at points A and B. Given `r_(1) lt r_(2)`, where will the strength of the magnetic field be larger?
Justify your answer in each case.

Text Solution

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(i) Maxwell's right hand thumb rule. The direction of the current is given by Maxwell's right hand thumb rule, "If the current carrying conductor is gripped with the right hand in such a way that the thumb gives the direction of the current, then the direction of the fingers gives the direction of hte magnetic field produced around the conductor". ltbrlt
(ii) Since the direction of current in the straight conductor is from Q to P, then according to Maxwell's right hand thumb rule, magnetic field at point A is inside the papaer and at point B is outside the paper. Since `r_(1) lt r_(2)` the strength of the magnetic field at A is more than at B because greater the distance of a point from the current carrying wire, weaker will be the magnetic field produced at that point.
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