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In Figure 3,DeltaABC and Delta XYZ are ...

In Figure `3,DeltaABC and Delta XYZ ` are show. If `AB=3cm, BC=6cm,AC=2sqrt3 cm, angle A =80^(@), angle B=60^(@), XY=4sqrt3cm, YZ=12 cm and XZ=6cm,` then find the value of `angle Y.`

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In figure - 3, triangleABC and triangleXYZ are shown. if AB = 3 CM, BC = 6 cm, AC = 2sqrt3 cm , angleA = 80^@ , angleB = 60^@ , XY = 4sqrt3 cm , YZ = 12 CM and XZ= 6 cm, then find the value of angleY

In figure - 3, triangleABC and triangleXYZ are shown. if AB = 3 CM, BC = 6 cm, AC = 2sqrt3 cm , angleA = 80^@ , angleB = 60^@ , XY = 4sqrt3 cm , YZ = 12 CM and XZ= 6 cm, then find the value of angleY

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X BOARD PREVIOUS YEAR PAPER ENGLISH-CBSE BOARDS 2020-SECTION B
  1. In Figure 3,DeltaABC and Delta XYZ are show. If AB=3cm, BC=6cm,AC=2sq...

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  2. Find the mean for the following distribution :

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  3. The following distribution shows the transport expenditure of 100 e...

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  4. Solve for x : 2x^(2) + 5 sqrt(5) x - 15=0

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  5. Check whether 6^(n) can end with the digit 0 (zero) for any natura...

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  6. If 5 tan theta = 4 , show that ( 5 sin theta - 3 cos theta)/(5 s...

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  7. 14 defective bulbs are accidentally mixed with 98 good ones. It is not...

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  8. if tan (A + B) = sqrt(3) and tan (A - B) = 1/ sqrt(3) , 0 (lt) A + B (...

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  9. If a letter is chosen at random from the English alphabet, find the pr...

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  10. Solve for x : sqrt3x^(2)+14x-5sqrt3=0

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  11. Find the mean for the following distribution :

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  12. The following distribution shows the transport expenditure of 100 expl...

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  13. Check whether 6^n can end with the digit 0 for any natural number n...

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  14. Find the LCM of 150 and 200.

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  15. In figure - 3, triangleABC and triangleXYZ are shown. if AB = 3 CM, BC...

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  16. A cone and a cylinder have the same radii but the height of the cone i...

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  17. In Figure, a quadrilateral ABCD is drawn to circumscribe a circle . ...

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  18. In Figure , find the perimeter of DeltaABC. If AP = 12 cm.

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  19. Find the mode of the following distribution :

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  20. In Figure , If PQ || BC and PR || CD, prove that (QB)/(AQ)=(DR)/(AR) .

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