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log2|x-1|<1...

`log_2|x-1|<1`

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To solve the inequality \( \log_2 |x - 1| < 1 \), we will follow these steps: ### Step 1: Rewrite the logarithmic inequality The inequality \( \log_2 |x - 1| < 1 \) can be rewritten in exponential form. Recall that if \( \log_b(a) < c \), then \( a < b^c \). So, we have: \[ |x - 1| < 2^1 ...
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