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Solve: (log)3(2x^2+6x-5)>1...

Solve: `(log)_3(2x^2+6x-5)>1`

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To solve the inequality \((\log)_3(2x^2 + 6x - 5) > 1\), we can follow these steps: ### Step 1: Rewrite the logarithmic inequality We start by converting the logarithmic inequality into an exponential form. The inequality \((\log)_3(2x^2 + 6x - 5) > 1\) can be rewritten as: \[ 2x^2 + 6x - 5 > 3^1 \] This simplifies to: ...
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