Solve : `(log)_(0. 3)(x^2-x+1)>0`

Explanation

To solve the inequality \( \log_{0.3}(x^2 - x + 1) > 0 \), we will follow these steps:

### Step 1: Understand the logarithmic inequality
The inequality \( \log_{0.3}(x^2 - x + 1) > 0 \) means that the argument of the logarithm, \( x^2 - x + 1 \), must be greater than \( 0.3^0 \) because the base \( 0.3 \) is less than 1.

### Step 2: Convert the logarithmic inequality
Since \( 0.3^0 = 1 \), we can rewrite the inequality as:
\[
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