Solve `4^((log)_9x)-6^((log)_9 2)+2^((log)_3 27)=0`

Explanation

`4^(log_9x) - 6x^(log_9 2)+2^(log_3 27) = 0`

`=>4^(log_9x) - 6*2^(log_9 x) +2^(log_3 2^3) = 0`

Let `2^(log_9 x) = t`,

Then,

`=>t^2 -6t +8 = 0`

`=>t^2-4t-2t+8 = 0`

`=>(t-4)(t-2) = 0`

`=>t = 2 or t = 4`

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