Let `a >1` be a real number. Then the number of roots equation `a^(2(log)_2x)=15+4x^((log)_2a)` is 2 (b) infinite (c) 0 (d) 1

Explanation

To solve the equation \( a^{2 \log_2 x} = 15 + 4 x^{\log_2 a} \) where \( a > 1 \), we will follow these steps:

### Step 1: Rewrite the equation using logarithmic properties
We start with the equation:
\[ a^{2 \log_2 x} = 15 + 4 x^{\log_2 a} \]
Using the property that \( a^{\log_b c} = c^{\log_b a} \), we can rewrite \( a^{2 \log_2 x} \) as:
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