If `(log)_(10)2=a ,(log)_(10)3=bt h e n(log)_(0. 72)(9. 6)` in terms of `a` and `b` is equal to (a) `(2a+3b-1)/(5a+b-2)` (b) `(5a+b-1)/(3a+2b-2)` (c) `(3a+b-2)/(2a+3b-1)` (d) `(2a+5b-2)/(3a+b-1)`

Explanation

To solve the problem of finding \((\log_{0.72} 9.6)\) in terms of \(a\) and \(b\), where \((\log_{10} 2 = a)\) and \((\log_{10} 3 = b)\), we can follow these steps:

### Step 1: Change of Base Formula
Using the change of base formula for logarithms, we can express \(\log_{0.72} 9.6\) as:
\[ \log_{0.72} 9.6 = \frac{\log_{10} 9.6}{\log_{10} 0.72} \]

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