Solve `(log)_4 8+(log)_4(x+3)-(log)_4(x-1)=2.`

Explanation

To solve the equation \( \log_4 8 + \log_4 (x+3) - \log_4 (x-1) = 2 \), we will follow these steps:

### Step 1: Combine the logarithms
Using the properties of logarithms, we can combine the logarithmic terms. Recall that:
- \( \log_a b + \log_a c = \log_a (b \cdot c) \)
- \( \log_a b - \log_a c = \log_a \left(\frac{b}{c}\right) \)

So, we can rewrite the equation as:
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