The general value of `theta` satisfying the equation `tan^2theta+sec2theta=1` is_____

Explanation

To solve the equation \( \tan^2 \theta + \sec 2\theta = 1 \), we will follow these steps:

### Step 1: Rewrite the equation
We know that \( \sec 2\theta = \frac{1}{\cos 2\theta} \). Therefore, we can rewrite the equation as:
\[ \tan^2 \theta + \frac{1}{\cos 2\theta} = 1 \]

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