Find the number of solution of the equation `e^(sinx)-e^(-sinx)-4=0`

Options

A. No real root
B. exactly one real root
C. exactly four real roots
D. infinite number of real roots

Explanation

To solve the equation \( e^{\sin x} - e^{-\sin x} - 4 = 0 \), we can follow these steps:

### Step 1: Rewrite the equation
Start by rewriting the equation:
\[ e^{\sin x} - e^{-\sin x} = 4 \]
This can be expressed as:
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