The general solution of the equation `sinx-3sin2x+sin3x=cosx-3cos2x+cos3x` is `(n in Z)` `npi+pi/8` (b) `(npi)/2+pi/8` `(-1)^n(npi)/2+pi/8` (d) `2npi+cos^(-1)2/3`

Explanation

To solve the equation \( \sin x - 3 \sin 2x + \sin 3x = \cos x - 3 \cos 2x + \cos 3x \), we will follow these steps:

### Step 1: Rearranging the Equation
We start with the equation:
\[ \sin x - 3 \sin 2x + \sin 3x - \cos x + 3 \cos 2x - \cos 3x = 0 \]

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