Find the values of a for which `a^2-6sinx-5ale0,Aax inR`.

Explanation

To solve the inequality \( a^2 - 6\sin x - 5a \leq 0 \) for values of \( a \) such that \( x \in \mathbb{R} \), we will follow these steps:

### Step 1: Rearranging the Inequality
We start with the given inequality:
\[ a^2 - 6\sin x - 5a \leq 0 \]
We can rearrange this as:
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