Solve : `(log)_((-x^2-6x)//10)(sin3x+sinx)=(log)_((-x^2-6x)//10)(sin2x)`

Explanation

To solve the equation

\[ \log_{(-\frac{x^2 + 6x}{10})}(\sin(3x) + \sin(x)) = \log_{(-\frac{x^2 + 6x}{10})}(\sin(2x), \]

we will follow these steps:

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