The area of a regular polygon of `n` sides is (where `r` is inradius, `R` is circumradius, and `a` is side of the triangle (a) `(n R^2)/2sin((2pi)/n)` (b) `n r^2tan(pi/n)` (c) `(n a^2)/4cotpi/n` (d) `n R^2tan(pi/n)`

The area of a regular polygon of n sides is (where r is inradius, R is circumradius, and a is side of the triangle) (n R^2)/2sin((2pi)/n) (b) n r^2tan(pi/n) (n a^2)/4cotpi/n (d) n R^2tan(pi/n)

If a regular polygon of n sides has circum radius R and inradius r then each side of polygon is:

the sum of the radii of inscribed and circumscribed circle of an n sides regular polygon of side a is (A) a/2 cot (pi/(2n)) (B) acot(pi/(2n)) (C) a/4 cos, pi/(2n)) (D) a cot (pi/n)

The area of the circle and the area of a regular polygon of n sides and the perimeter of polygon equal to that of the circle are in the ratio of tan(pi/n):pi/n (b) cos(pi/n):pi/n sinpi/n :pi/n (d) cot(pi/n):pi/n

If r is the radius of inscribed circle of a regular polygon of n-sides ,then r is equal to

A B C is an equilateral triangle of side 4c mdot If R , r, a n d,h are the circumradius, inradius, and altitude, respectively, then (R+r)/h is equal to (a) 4 (b) 2 (c) 1 (d) 3

Let A_n be the area that is outside a n-sided regular polygon and inside its circumscribeing circle. Also B_n is the area inside the polygon and outside the circle inscribed in the polygon. Let R be the radius of the circle circumscribing n-sided polygon. On the basis of above information, answer the equation If n=6\ then A_n is equal to R^2((pi-sqrt(3))/2) (b) R^2((2pi-6sqrt(3))/2) R^2(pi-sqrt(3)) (d) R^2((2pi-3sqrt(3))/2)

If n=4\ then B_n is equal to : R^2((4-pi))/2 (b) (R^2(4-pisqrt(2)))/2 R^2((4sqrt(2)-pi))/2 (d) none of these

The value of lim_(n->oo) [tan(pi/(2n)) tan((2pi)/(2n))........tan((npi)/(2n))]^(1/n) is

If R is the radius of circumscribing circle of a regular polygon of n-sides,then R =