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If cos(A+B+C)=cosAcosBcosC , then find t...

If `cos(A+B+C)=cosAcosBcosC ,` then find the value of `(8sin(B+C)sin(C+A)sin(A+B))/(sin2Asin2Bsin2C)`

A

`8`

B

`4`

C

`-3`

D

`-1`

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The correct Answer is:
D
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