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Find common roots of the equations 2sin^...

Find common roots of the equations `2sin^2x+sin^2 2x=2a n dsin2x+cos2x=tanxdot`

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To find the common roots of the equations \(2\sin^2 x + \sin^2 2x = 2\) and \(\sin 2x + \cos 2x = \tan x\), we will solve each equation step by step and then find the common solutions. ### Step 1: Solve the first equation \(2\sin^2 x + \sin^2 2x = 2\) 1. **Rewrite \(\sin^2 2x\)**: \[ \sin^2 2x = (2\sin x \cos x)^2 = 4\sin^2 x \cos^2 x \] ...
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CENGAGE ENGLISH-TRIGONOMETRIC FUNCTIONS-All Questions
  1. If sinx+sin y+sinz+sinw=-4, then the value of sin^(400)x+sin^(300)y+s...

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  2. Prove that cos20^0cos40^0cos60^0cos80^0=1/(16)dot

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  3. Find common roots of the equations 2sin^2x+sin^2 2x=2a n dsin2x+cos2x=...

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  4. The sides of a triangle are in A.P. and its area is 3/5t h of the an e...

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  5. If 1+sinx+sin^2x+sin^3x+oo is equal to 4+2sqrt(3),0ltxltpi, then xis ...

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  6. If K=sin(pi/(18))sin((5pi)/(18))sin((7pi)/(18)), then the numerical va...

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  7. One of the general solutions of 4sin^4x+cos^4x=1 is

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  8. The value of the expression (tan^2 20^0-sin^2 20^0)/(tan^2 20^0+sin^2 ...

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  9. A piece of paper is in the shape of a square of side 1m long. It is cu...

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  10. If sinx+cosx=(sqrt(7))/2, where x in 1s t quadrant, then tanx/2 is ...

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  11. If tantheta+sectheta=1. 5 , find sintheta,tantheta and secthetadot

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  12. Show that the line joining the incenter to the circumcenter of triangl...

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  13. For n in Z , the general solution of (sqrt(3)-1)sintheta+(sqrt(3)+1)c...

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  14. The value of cot70^0+4cos70^0 is (a)1/(sqrt(3)) (b) sqrt(3) (c) ...

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  15. In A B C , right-angled at C , if tanA=sqrt((sqrt5-1)/2) , show tha...

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  16. If cosectheta-sintheta=m a n d sectheta-costheta=n ,"eliminate"theta

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  17. The solution of 4sin^2x+tan^2x+cos e c^2x+cot^2x-6=0i s(n in Z) (a) ...

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  18. The value of sinpi/(14)sin(3pi)/(14)sin(5pi)/(14)sin(7pi)/(14)sin(9pi)...

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  19. If 3sintheta+5costheta=5, then show that 5sintheta-3costheta=+-3.

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  20. In A B C , if (sinA)/(csinB)+(sinB)/c+(sinC)/b=c/(a b)+b/(a c)+a/(b c...

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