The solution of `4sin^2x+tan^2x+cos e c^2x+cot^2x-6=0i s(n in Z)` (a) `npi+-pi/4` (b) `2npi+-pi/4` `npi+pi/3` (d) `npi-pi/6`

Explanation

To solve the equation \( 4\sin^2 x + \tan^2 x + \csc^2 x + \cot^2 x - 6 = 0 \), we can follow these steps:

### Step 1: Rewrite the equation
We start with the given equation:
\[ 4\sin^2 x + \tan^2 x + \csc^2 x + \cot^2 x - 6 = 0 \]
We know the relationships between the trigonometric functions:
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