In ` A B C ,` if `(sinA)/(csinB)+(sinB)/c+(sinC)/b=c/(a b)+b/(a c)+a/(b c),` then the value of angle `A` is `120^0` (b) `90^0` (c) `60^0` (d) `30^0`

Explanation

To solve the given problem, we will follow these steps systematically:

### Step 1: Understand the given equation
We are given the equation:
\[ \frac{\sin A}{c \sin B} + \frac{\sin B}{c} + \frac{\sin C}{b} = \frac{c}{ab} + \frac{b}{ac} + \frac{a}{bc} \]
This equation relates the angles and sides of triangle \(ABC\).
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