If the hypotenuse of a right-angled triangle is four times the length of the perpendicular drawn from the opposite vertex to it, then the difference of the two acute angles will be `60^0` (b) `15^0` (c) `75^0` (d) `30^0`

Explanation

To solve the problem, we need to analyze the relationship between the hypotenuse, the perpendicular, and the angles in a right-angled triangle.

### Step-by-Step Solution:

1. **Understanding the Triangle**:
Let's denote the right-angled triangle as ABC, where angle C is the right angle. Let D be the foot of the perpendicular from vertex B to side AC. According to the problem, the hypotenuse AB is four times the length of the perpendicular BD.

2. **Assigning Lengths**:
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