If `sin2theta=cos3theta"and"theta` is an acute angle, then `sintheta` equal (a)`(sqrt(5)-1)/4` (b) `-((sqrt(5)-1)/4)` (c)`(sqrt(5)+1)/4` (d) `(-sqrt(5)-1)/4`

If sin5theta=cos4theta, whre 5thetaa n d4theta are acute angles, find the value of theta .

If tan\ theta/2=(cosec theta-sin theta), then tan^2\ theta/2 may be equal to (A) 2-sqrt(5) (B) (9-4sqrt(5))(2+sqrt(5)) (C) -2+sqrt(5) (D) (9-4sqrt(5))(2-sqrt(5))

If the tangent drawn at point (t^2,2t) on the parabola y^2=4x is the same as the normal drawn at point (sqrt(5)costheta,2sintheta) on the ellipse 4x^2+5y^2=20, then theta=cos^(-1)(-1/(sqrt(5))) (b) theta=cos^(-1)(1/(sqrt(5))) t=-2/(sqrt(5)) (d) t=-1/(sqrt(5))

If theta is an acute angle and sin((theta)/(2))=sqrt((x-1)/(2x)) ,then tan theta is equal to

If theta and 2theta-45^@ are acute angles such that sintheta=cos(2theta-45^@) , then tantheta is equal to (a) 1 (b) -1 (c) sqrt(3) (d) 1/(sqrt(3))

Find an acute angle theta , when (costheta-sintheta)/(costheta+sintheta)=(1-sqrt(3))/(1+sqrt(3))

If x=sqrt(5)+\ 2, then x-1/x equals (a) 2sqrt(5) (b) 4 (c) 2 (d) sqrt(5)

The sum of all the solution(s) of the equation sin^(-1)2x=cos^(-1)x is 0 (2) 2/(sqrt(5)) (3) 1/(sqrt(5)) (4) (-1)/(sqrt(5))

If t a ntheta=-1/(sqrt(5)) and theta lies in the IV quadrant, then the value of costheta is a. (sqrt(5))/(sqrt(6)) b. 2/(sqrt(6)) c. 1/2 d. 1/(sqrt(6))

cos theta=sqrt(1-sin theta)