If `theta_1` and `theta_2` are two values lying in `[0,2pi]` for which `t a ntheta=lambda,` then `tan((theta_1)/2)tan((theta_2)/2)` is equal to (a)0 (b) `-1` (c) 2 (d) 1

Explanation

To solve the problem, we need to find the product \( \tan\left(\frac{\theta_1}{2}\right) \tan\left(\frac{\theta_2}{2}\right) \) given that \( \tan \theta = \lambda \) for two angles \( \theta_1 \) and \( \theta_2 \).

### Step-by-step Solution:

1. **Start with the given equation**:
\[ \tan \theta = \lambda \]
...