The equation `sin^2theta=(x^2+y^2)/(2x y),x , y!=0` is possible if

Explanation

To solve the equation \( \sin^2 \theta = \frac{x^2 + y^2}{2xy} \) under the condition that \( x, y \neq 0 \), we need to find the conditions under which this equation holds true.

### Step-by-Step Solution:

1. **Understanding the Range of \( \sin^2 \theta \)**:
\[ \sin^2 \theta \text{ lies in the range } [0, 1]. \]
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