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If `b >1,sint >0,cost >0a n d(log)_b(sint)=x ,t h e n(log)_b(cost)` is equal to `1/2(log)_b(a-b^(2x))` (b) `2log(1-b^(x/2))` `(log)_bsqrt(1-b^(2x))` (d) `sqrt(1-x^2)`

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To solve the problem, we need to find the value of \( \log_b(\cos t) \) given that \( \log_b(\sin t) = x \). ### Step-by-Step Solution: 1. **Use the property of logarithms**: Given \( \log_b(\sin t) = x \), we can rewrite this in exponential form: \[ \sin t = b^x ...
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