A sector `O A B O` of central angle `theta` is constructed in a circle with centre `O` and of radius `6.` The radius of the circle that is circumscribed about the triangle `O A B ,` is `6costheta/2` (b) `6sectheta/2` `3sectheta/2` (d) `3(costheta/2+2)`

Explanation

To find the radius of the circumcircle of triangle OAB, we can follow these steps:

### Step 1: Understand the triangle OAB
We have a triangle OAB where:
- OA = OB = radius of the circle = 6
- Angle AOB = θ

### Step 2: Find the length of side AB
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