If roots of the equation `2x^2-4x+2sintheta-1=0` are of opposite sign, then `theta` belongs to `(pi/6,(5pi)/6)` (b) `(0,pi/6)uu((5pi)/6,pi)` `((13pi)/6,(17pi)/6)` (d) `(0,pi)`

For 0 cos^(-1)(sintheta) is true when theta belongs to (a) (pi/4,pi) (b) (pi,(3pi)/2) (c) (pi/4,(3pi)/4) (d) ((3pi)/4,2pi)

Given both thetaa n dphi are acute angles and sintheta=1/2,cosvarphi=1/3, then the value of theta+varphi belongs to (a) (pi/3,pi/2] (b) (pi/2,(2pi)/3] (c) ((2pi)/3,(5pi)/6] (d) ((5pi)/6,pi]

cos^-1 {-sin((5pi)/6)}= (A) - (5pi)/6 (B) (5pi)/6 (C) (2pi)/3 (D) -(2pi)/3

If both roots of quadratic equation x^2+(sintheta+costheta)x+3/8=0 are positive and distinct then complete set of value of theta in [0,2pi] is (1) (pi/(12),(5pi)/(12)) (2) ((13pi)/(12),(17pi)/(12)) (3)((7pi)/(12),(11pi)/(12)) (4) ((19pi)/(12),(23pi)/(12))

A solution of the equation cos^2theta+sintheta+1=0 lies in the interval a. (-pi//4,pi//4) b. (pi//4,3pi//4) c. (3pi//4,5pi//4) d. (5pi//4,7pi//4)

If the equation x^2 +4x sintheta + tantheta=0\ (0 < theta < pi/2) has repeated roots, then theta equals (i) pi/12 (ii) pi/6 (iii) pi/12 or (5pi)/12 (iv) pi/6 or pi/12

The solution(s) of the equation cos2x sin6x=cos3x sin5x in the interval [0,pi] is/are pi/6 (b) pi/2 (c) (2pi)/3 (d) (5pi)/6

The value of theta in (0,2pi) for which 2sin^2theta-5sintheta+2>0 is (0,pi/6)uu((5pi)/6,2pi) (b) (pi/8,(pipi)/6) (0,pi/8)uu(pi/6pi/6) (d) ((41pi)/(48),pi)

The least positive solution of cot(pi/(3sqrt3) sin2x)=sqrt3 lie (a) (0,pi/6) (b) (pi/9,pi/6) (c) (pi/12,pi/9) (d) (pi/3,pi/2)

One of the root equation cosx-x+1/2=0 lies in the interval (0,pi/2) (b) (-pi/(2,0)) (c) (pi/2,pi) (d) (pi,(3pi)/2)