If `x, y in [0,2pi]` then find the total number of order pair `(x,y)` satisfying the equation `sinx .cos y = 1`

Explanation

To solve the equation \( \sin x \cdot \cos y = 1 \) for \( x, y \in [0, 2\pi] \), we will follow these steps:

### Step 1: Analyze the equation
The equation \( \sin x \cdot \cos y = 1 \) implies that both \( \sin x \) and \( \cos y \) must take values that multiply to 1. Since the maximum value of both \( \sin x \) and \( \cos y \) is 1, we can conclude that:

\[ \sin x = 1 \quad \text{and} \quad \cos y = 1 \]
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