If `3sinbeta=sin(2alpha+beta)` then `tan(alpha+beta)-2tanalpha` is (a)independent of `alpha` (b)independent of `beta` (c)dependent of both `alpha` and `beta` (d)independent of both `alpha` and `beta`

Explanation

To solve the problem, we start with the given equation:

**Given:**
\[ 3 \sin \beta = \sin(2\alpha + \beta) \]

We need to find the expression:
\[ \tan(\alpha + \beta) - 2 \tan \alpha \]

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