In an equilateral triangle, three coins of radii 1 unit each are kept so that they touch each other and also the sides of the triangle. The area of the triangle is 2sqrt(3)` (b) `6+4sqrt(3)` `12+(7sqrt(3))/4` (d) `3+(7sqrt(3))/4`

The area of an equilateral triangle with side 2sqrt3 cm is

An equilateral triangle S A B is inscribed in the parabola y^2=4a x having its focus at Sdot If chord A B lies towards the left of S , then the side length of this triangle is 2a(2-sqrt(3)) (b) 4a(2-sqrt(3)) a(2-sqrt(3)) (d) 8a(2-sqrt(3))

The side of an equilateral triangle is 6sqrt(3) cm. Find the area of the triangle. [Take sqrt(3)=1.732 ]

Each side of an equilateral triangle is equal to the radius of a circle whose area is 154\ c m^2dot The area of the triangle is (a) (7sqrt(3))/4\ c m^2 (b) (49sqrt(3))/2\ c m^2 (c) (49sqrt(3))/4\ c m^2 (d) (7sqrt(3))/2\ c m^2

What is the area of a triangle whose vertices are (0, 6 sqrt(3)), (sqrt(35, 7)) , and (0, 3) ?

In an equilateral triangle with side a, prove that the altitude is of length (a sqrt3)/2

Find the angles of the triangle whose sides are 3+ sqrt3, 2sqrt3 and sqrt6.

If A is the area an equilateral triangle of height h , then (a) A=sqrt(3)\ h^2 (b) sqrt(3)A=h (c) sqrt(3)A=h^2 (d) 3A=h^2

On the line segment joining (1, 0) and (3, 0) , an equilateral triangle is drawn having its vertex in the fourth quadrant. Then the radical center of the circles described on its sides. (a) (3,-1/(sqrt(3))) (b) (3,-sqrt(3)) (c) (2,-1sqrt(3)) (d) (2,-sqrt(3))

One angle of an isosceles triangle is 120^0 and the radius of its incircle is sqrt(3)dot Then the area of the triangle in sq. units is (a) 7+12sqrt(3) (b) 12-7sqrt(3) (c) 12+7sqrt(3) (d) 4pi